9x^2+142=142

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Solution for 9x^2+142=142 equation: 



9x^2+142=142

We move all terms to the left:

9x^2+142-(142)=0

We add all the numbers together, and all the variables

9x^2=0

a = 9; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·9·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{18}=0$

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